x^2+x+7^2=2x+3^2

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Solution for x^2+x+7^2=2x+3^2 equation: 



x^2+x+7^2=2x+3^2

We move all terms to the left:

x^2+x+7^2-(2x+3^2)=0

We add all the numbers together, and all the variables

x^2+x-(2x+3^2)+49=0

We get rid of parentheses

x^2+x-2x+49-3^2=0

We add all the numbers together, and all the variables

x^2-1x+40=0

a = 1; b = -1; c = +40;
Δ = b2-4ac
Δ = -12-4·1·40
Δ = -159
Delta is less than zero, so there is no solution for the equation

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